How to make a 2.88Meg Boot-CD with GRUB

There is a description from Mohamed Kamil Nizam Mansor on 08-July-2002. Find it here: http://linux-sxs.org/grubcdboot.html

This document is an updated version with some enhancements:
It shows how to create a bootable CD with GRUB. It uses a 2.88Meg image, because kernel and initrd will not fit into a 1.44meg image.

1. create an image file using dd with size 2.88Mb

# dd if=/dev/zero of=/tmp/cdboot.288 bs=1k count=2880

2. get associate with loop device (my case, I using /dev/loop1)

# losetup /dev/loop1 /tmp/cdboot.288

3. create msdos file system

# mkfs -V -t msdos /dev/loop1

4. mount the image file (I use /mnt as mountpoint)

# mount /dev/loop1 /mnt

5. Copy grub's files into the image

# mkdir /mnt/boot
# mkdir /mnt/boot/grub
# cd /boot/grub
# cp stage1 stage2 splash.xpm.gz menu.lst /mnt/boot/grub

6. Copy kernel and initrd into the image (add more files as needed)

# cd /boot
# cp vmlinuz initrd /mnt/boot/

7. Edit the menu-file, insert something like:
title Linux from CD
kernel (fd0)/boot/vmlinuz
initrd (fd0)/boot/initrd

# vi /mnt/boot/grub/menu.lst
# umount /mnt

8. Install grub in the image (umount /mnt first!)

# grub (Start the grub shell, then enter:)
device (fd0) /dev/loop1
root (fd0)
setup (fd0)
quit

9. Don't forget to divorce the loop-Device:

# losetup -d /dev/loop1

9. Write the image to a CD, for example with mkisofs & cdrecord: (have to insert the correct dev=?,?,? with cdrecord)

# mkdir /tmp/mycd
# cp /tmp/cdboot.288 /tmp/mycd
# mkisofs -b cdboot.288 -c boot.catalog -J /tmp/mycd | cdrecord speed=8 dev=0,0,0

I will be grateful for any feedback to this article. Email: rm@moosauer.de